### magnetic meridian is the plane perpendicular to

Real dip theta=40.9^@ Let the vertical component of earth's magnetic field be V and its horizontal component at magnetic meridian be H. Then the angle of dip theta at magnetic meridian will be given by tantheta=V/H.....[1] When the dip needle is suspended at an angle of 30^@ to the earth magnetic meridian then it makes an angle 45^@ with the horizontal. The time period of vibration is found to be 2 seconds. The needle will stay (a) in horizontal direction only (b) in vertical direction only (c) in any direction except vertical and horizontal (d) in the direction it is released Magnetic meridian is the plane . To get the true heading, you need to first read the magnetic compass, then either add an Easterly, or subtract a Westerly, magnetic variation; based on the isogonic lines. A dip circle is taken to geomagnetic equator. Click hereto get an answer to your question ️ A vertical circular coil of radius 0.1 m and having 10 turns carries a steady current. An electron with charge -e and mass m travels at a speed v in a plane perpendicular to a magnetic field of magnitude B. A voltage measured perpendicular to the plane is indicative of the CME of hot electrons. Then the angle of dip is (a) 0° (b) 30° (c) 45° (d) 90° Maharashtra State Board HSC Science (Electronics) 11th. Illustration of a thin-film CME measurement geometry in the presence of a strong in-plane electric field (E). The time period of vibration is found to be 2 sec. Important Solutions 17 ... perpendicular to the magnetic axis of Earth. If the magnetic field is increased from 0.01 T to 0.06 T during a time interval of … Then the angle of dip is A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. Reuse & Permissions × The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 seconds. The magnitude of the horizontal component of the earth ' magnetic field at the place is known to be . What is the amount of work done by the magnetic field? passing through the magnetic axis of Earth. East of this agonic line, the magnetic North Pole is to the west of the geographic North Pole and a correction must be applied to a compass indication to get a true direction. If BH = 0.314 × 10^-4 T , the current in the coil is : The same needle is then allowed to vibrate in the horizontal plane and the time period is again found to be 2 sec. The needle is allowed to move in a vertical plane perpendicular to the magnetic meridian. Another magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at with the horizontal . The horizontal component of the earth’s magnetic field at the place is known to be 0.35 G. Determine the magnitude of the earth’s magnetic field at … For a vertical plane other than magnetic meridian $\alpha>0$ or $\cos \alpha<1$ so $\theta^{\prime}>\theta$ In a vertical plane other than magnetic meridian angle of dip is more than in magnetic meridian. A magnetic field is directed perpendicular to the plane of a circular coil of area 0.2 m² and 250 turns. The box is then rotated through 90 o position on the horizontal circular scale. Textbook Solutions 6926. The electron follows a circular path of radius R. In a time, t, the electron travels halfway around the circle. A magnetic field B is applied perpendicular to the plane of the sample. A dip needle vibrates in the vertical plane perpendicular to the magnetic meridian. A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22° with the horizontal. Here the needle and vertical scale are in a plane perpendicular to the magnetic meridian. 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